_Trip_ , those are definitely polar compounds, check out their molecular structure, they have many OH groups. Oxygen is an electronegative element which draws electron density away from other less electronegative elements that are covalently bonded to it (for example carbon and hydrogen). This leaves the other elements with a partially positive charge and the oxygen with a partially negative charge, two poles.

At the same time, you don't have any hydrophobic (non-polar) tail in those flavonoids, which would be composed of only carbon and hydrogen (hydrocarbon). Carbon and hydrogen only have a small difference in electronegativity (under 0.5), so do not create partial negative and positive charges within the molecule.  If you look at non-polar molecules like pentane hexane etc  you'll see they don't have electronegative elements.

Soap molecules have both hydrophobic tail and a hydrophilic (polar) head, which is why it helps oils mixing with water and being washed away.

Now a question for the experts, why is THC mostly non-polar even though it has an OH group and an oxygen? Is it because the hydrophobic tail is more exposed therefore it has more interaction with non-polar solvents, while the more polar OH and O are stericly hindered due to being "surrounded" by other carbon and hydrogens and therefore don't interact much with polar solvents?

Now back to bufotenine/yopo subject: Brennendes Wasser, you talk several times about other alkaloids, polar alkaloids being removed, etc.  Do you have any evidence of those alkaloids being there at all, for example analyzing the results that are left behind after step 5?