So I want to make a Calea ternifolia (aka zacatechichi) extract in the fashion presented in this paper: Mayagoitia, L; Diaz, J; Contreras, C (1986). "Psychopharmacologic analysis of an alleged oneirogenic plant: Calea zacatechichi". Journal of Ethnopharmacology 18 (3): 229–43. doi:10.1016/0378-8741(86)90002-4. PMID 3821139.
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The hexane should be no problem, I'll use a low boiling Petroleum ether (40-60 °C). However, in order to save money, I'd like to replace the Methanol. I know that Methanol is a great polar protic solvent - the next best thing to it in my stock is Acetone and IPA. I'd like to do an Acetone pull first, because it's easier to evaporate than IPA. I see that Acetone lacks an H to form additional bonds, but this can be fixed by a second IPA pull.
My question now is: do Acetone and IPA form new (and unwanted) compounds, when replacing the MeOH? In the paper they've tested the MeOH extract thoroughly, but with the new twist I'm a little bit worried.
Or is a polar pull with water no different than a polar pull with Acetone or MeOH? Maybe someone could give me a hint towards the underlying principle. Thanks!
Quote:
One kilogram of the dried plant (stem and leaves)
was mashed and extracted with hexane until exhaustion [..]
The remaining material was thoroughly extracted with methanol
and the organic fraction evaporated.
The hexane should be no problem, I'll use a low boiling Petroleum ether (40-60 °C). However, in order to save money, I'd like to replace the Methanol. I know that Methanol is a great polar protic solvent - the next best thing to it in my stock is Acetone and IPA. I'd like to do an Acetone pull first, because it's easier to evaporate than IPA. I see that Acetone lacks an H to form additional bonds, but this can be fixed by a second IPA pull.
My question now is: do Acetone and IPA form new (and unwanted) compounds, when replacing the MeOH? In the paper they've tested the MeOH extract thoroughly, but with the new twist I'm a little bit worried.
Or is a polar pull with water no different than a polar pull with Acetone or MeOH? Maybe someone could give me a hint towards the underlying principle. Thanks!