The Day Tripper
Rennasauce Man
So i just finished salting my first d-limo pull off of a 100g a/b i was doing. I initially salted out as the hcl, but it would not dry so i added some water and tossed it back into the base solution. I then proceeded to pull again with d-limo, and then then salted with fasw. I used 410mg of fumaric acid, and approx 75ml of distilled water. Shook the hell out of the mixture every so often, and let it sit for a good 12 hours.
After decanting off the fasw, and evaporating it, i yielded 1.86g of really white and sparkly dry (not oily) fumarates. This seems a little excessive to me (not complaining lol), being that i only used 410mg of fumaric acid. I was under the assumption that fumaric acid made up approx %30 of the weight of the salt, so i did some math and 1.86 * .3 (%30) came out as .558. That would mean assuming its relatively pure i would have needed 558mg of fumaric acid to get that amount of dmt fumarate. Is this the correct way to make the calculation?
I am doing a dry acetone wash as I'm typing this up, but am wondering how i got so much from only 410mg of fumaric acid, and distilled water (no extra salts like tap water).
Any ideas or comments?
Thanks-
Edit- 1.75g after washing 2x with acetone.
NVM, i figured it out. Guess i was doing shoddy math. If dmt has a molecular weight of ~188, and fumaric acid ~116, then two dmts and a fumaric acid molecule would weigh 492 molecular weights. So that divided by the molecular weight of fumaric acid ~116 is .23, or %23 percent by weight. Now my numbers match up pretty good, thats ~405 mg fumaric acid for 1.75g of dmt fumarate. Pretty decent for a first pull I'd say.
After decanting off the fasw, and evaporating it, i yielded 1.86g of really white and sparkly dry (not oily) fumarates. This seems a little excessive to me (not complaining lol), being that i only used 410mg of fumaric acid. I was under the assumption that fumaric acid made up approx %30 of the weight of the salt, so i did some math and 1.86 * .3 (%30) came out as .558. That would mean assuming its relatively pure i would have needed 558mg of fumaric acid to get that amount of dmt fumarate. Is this the correct way to make the calculation?
I am doing a dry acetone wash as I'm typing this up, but am wondering how i got so much from only 410mg of fumaric acid, and distilled water (no extra salts like tap water).
Any ideas or comments?
Thanks-
Edit- 1.75g after washing 2x with acetone.
NVM, i figured it out. Guess i was doing shoddy math. If dmt has a molecular weight of ~188, and fumaric acid ~116, then two dmts and a fumaric acid molecule would weigh 492 molecular weights. So that divided by the molecular weight of fumaric acid ~116 is .23, or %23 percent by weight. Now my numbers match up pretty good, thats ~405 mg fumaric acid for 1.75g of dmt fumarate. Pretty decent for a first pull I'd say.