goddywoddy
Rising Star
Hello,
I am currently working on a theoretical tek for a crude extract of muscimol from Amanita muscaria. I've read the rules, and want to note that this is not an illicit drug, so I think this subject should be allowed here. It's an interesting subject from an organic chemistry perspective.
Well-dried Amanita muscaria were allowed to simmer in plain water. Both ibotenic acid and muscimol, the interesting compounds in this procedure, is water soluble. The heat should decarboxylate all the ibotenic acid into muscimol. The temperature was kept at max 60°C to prevent breakdown of muscimol, as it has a boiling point of 70°C. After an hour the mushrooms were filtered of, and the water was kept at a constant temperature of 60°C with a fan next to it for over two days, in order to reduce the solution to a resin.
Now, this resin is far from pure, and therefore I'm trying to find an easy way to clean it further. Muscimol has a pKa of 4.8, which means that at pH 2-3, 99.8-98.4% of the muscimol should be in salt form. By using 35% acetic acid, which have a pH of 2, the solution should be at pH ~2-3. Then one could pull with a non-polar, maybe heptane or perhaps d-limonene, which should pull the muscimol acetate. This could be basified and further cleaned if needed. Does this procedure seem correct? Will muscimol in fact become an acetate, and will it be pulled by a non-polar?
Perhaps I'm going at this the wrong way, maybe I should find a solvent that muscimol isn't soluble in, that will remove much of the other gunk? Maybe you have some other thoughts or theories? Please do share everything that comes to mind! Thanks in advance!
Additional bits of information: Muscimol is an extremely polar compound with a XLogP3 of -1.4. Muscimol is very soluble in water and methanol, slightly soluble in ethanol, DMSO and DMF.
I am currently working on a theoretical tek for a crude extract of muscimol from Amanita muscaria. I've read the rules, and want to note that this is not an illicit drug, so I think this subject should be allowed here. It's an interesting subject from an organic chemistry perspective.
Well-dried Amanita muscaria were allowed to simmer in plain water. Both ibotenic acid and muscimol, the interesting compounds in this procedure, is water soluble. The heat should decarboxylate all the ibotenic acid into muscimol. The temperature was kept at max 60°C to prevent breakdown of muscimol, as it has a boiling point of 70°C. After an hour the mushrooms were filtered of, and the water was kept at a constant temperature of 60°C with a fan next to it for over two days, in order to reduce the solution to a resin.
Now, this resin is far from pure, and therefore I'm trying to find an easy way to clean it further. Muscimol has a pKa of 4.8, which means that at pH 2-3, 99.8-98.4% of the muscimol should be in salt form. By using 35% acetic acid, which have a pH of 2, the solution should be at pH ~2-3. Then one could pull with a non-polar, maybe heptane or perhaps d-limonene, which should pull the muscimol acetate. This could be basified and further cleaned if needed. Does this procedure seem correct? Will muscimol in fact become an acetate, and will it be pulled by a non-polar?
Perhaps I'm going at this the wrong way, maybe I should find a solvent that muscimol isn't soluble in, that will remove much of the other gunk? Maybe you have some other thoughts or theories? Please do share everything that comes to mind! Thanks in advance!
Additional bits of information: Muscimol is an extremely polar compound with a XLogP3 of -1.4. Muscimol is very soluble in water and methanol, slightly soluble in ethanol, DMSO and DMF.
