Can someone explain the raw chemistry of the Lye and Naphta TEK?

[JustAQuestion]

I just wondering why it is working ? I am totally stupid to chemistry. Non polar solvent gives the dmt the N? Like N-N-DMT? Sorry for being stupid lol.

 

[downwardsfromzero]

The latter part of your question is a nomenclature issue. The "N" refers to the methyl groups being attached to the sidechain nitrogen atom. To distinguish this nitrogen atom from the indolic nitrogen atom in the DMT molecule, it's more properly written as "N',N'-DMT".

To learn about chemistry, follow the links in, e.g., this post

 

[JustAQuestion]

The latter part of your question is a nomenclature issue. The "N" refers to the methyl groups being attached to the sidechain nitrogen atom. To distinguish this nitrogen atom from the indolic nitrogen atom in the DMT molecule, it's more properly written as "N',N'-DMT".

To learn about chemistry, follow the links in, e.g., this post

Thank you very much! I read the basics chemistry forum but did not found this answer. So this molecule is in the root bark, and the lye and naphta just getting out the molecule somehow.

 

[downwardsfromzero]

Please read this post!

In basic solutions (e.g. lye) DMT is deprotonated [a state known as the free base] and thus more soluble in NPS (e.g. naphtha) as it carries no charge.

In acidic solutions DMT is protonated and thus more soluble in polar solvents such as water.

Because naphtha does not mix with water, we can easily separate the two, and by changing the pH of the water we can make DMT migrate from one phase to the other accordingly as required.

 

[JustAQuestion]

Please read this post!

In basic solutions (e.g. lye) DMT is deprotonated [a state known as the free base] and thus more soluble in NPS (e.g. naphtha) as it carries no charge.

In acidic solutions DMT is protonated and thus more soluble in polar solvents such as water.

Because naphtha does not mix with water, we can easily separate the two, and by changing the pH of the water we can make DMT migrate from one phase to the other accordingly as required.

Omg Thank you . I thought exactly that explanation! Thank you very much!