If you start with 6 mol/l of acetic acid (lets call it HA) and 50% dissociates, that would leave 3 mol/l HA and add 3 mol/l A- and 3 mol/l H+. Note that I write add because there may have been any amount of H+ present in the solution.afterwards said:Now I'm wondering what the Ka of a substance is at 50% dissociation. If Ka=[A-][H+]/AH then e.g. if you have 6 moles of acetic acid and it's 50% dissociated, then you would have 3 moles of H+ and 3 moles of CH3CO2. Wouldn't that mean 3x3/6?
If we assume that there is no other source of H+, the formula [A-]x[H+]/[HA]
would yield: 3x3/3. The pKa for the hypothetical HA is 10log(3), or about 0.477