I do get it, really, you are proposing there could be a system where the work you get out of the mechanical part [which would be less than (the density of the water) x (acceleration due to gravity) x (the volume of the object) x (the height of the water column); i.e., buoyant force x distance--which is the amount of work needed to get the buoyant object to the surface, if you try to extract more work from that part of the cycle the object will not rise] is greater than the work required to either disassemble or reassemble the object (because only one of those can be spontaneous without running afoul of thermodynamics) plus the work required to transport it back down so the cycle can start over (otherwise you are relying on either "magic" or an external force, i.e., either impossible or not really perpetual motion).SWIMfriend said:But there's no CAUSAL CHAIN between the chemistry of a buoyant object, and the AMOUNT of energy it can produce from MECHANICAL means, from the static force of the pressure in the column. In this case, you can't say "Well, it wouldn't work, because the energy from the mechanical system IS WHAT MAKES the chemical change. The chemical change is an ENTIRELY DIFFERENT SYSTEM--which will simply have a measurable energy cost. And that cost won't in ANY WAY be related to the mechanical goings on of the apparatus. That means it's just COINCIDENCE whether the chemical cost happens to be higher or lower than the mechanical output.
SWIMfriend said:I'm saying suppose the ENTIRE ENERGY REQUIREMENT for the object phase changes, entropy, etc., is LESS than can be produced by the apparatus. Of course I know (just from practical knowledge) that it WOULDN'T be; but my point is that doesn't HAVE TO BE THE CASE--it only HAPPENS to be the case by "coincidence."
This is my MAIN POINT, but no one seems to really be absorbing it.
Tsehakla said:It doesn't really matter if the connection between the proposed mechanical and chemical parts of the system are direct/"causal" or indirect, because unless it is a closed system you don't have perpetual motion (as entropymancer pointed out).
Now, if you were to back away from the perpetual motion claim and try to use the ocean (or atmosphere) as an infinite capacity heat sink you would be in much the same game as the wave->energy and wind->energy people... and the question becomes, `can it be done more efficiently?'
could one use a buoyant object that merely becomes "water logged" at a slow rate? It would go up the tube, but eventually come down as it got water-logged. When it comes down you catch it at the bottom of the tube, lift it the very short distance out of the water, and see if it becomes UN-water logged. In that case it seems the costs are the insertion of the buoyant object into the water, and the pulling of the water-logged object out of the water--both over very short distances.
Tsehakla said:However, we can assume that the work required to transport the formerly buoyant object back down to the bottom, regardless of its form, will at least be equal to the work it took to get it to the surface because the same amount of mass needs to be moved the same distance.
Entropymancer said:SWIMfriend said:I'm saying suppose the ENTIRE ENERGY REQUIREMENT for the object phase changes, entropy, etc., is LESS than can be produced by the apparatus. Of course I know (just from practical knowledge) that it WOULDN'T be; but my point is that doesn't HAVE TO BE THE CASE--it only HAPPENS to be the case by "coincidence."
This is my MAIN POINT, but no one seems to really be absorbing it.
I guess I'm just not sure how it's relevant if we're looking at it from the view of energy in the system.
Running the machine does work, but in so doing removes energy from the system. This work cannot be used to put more energy back into the system than it has taken out (I assume you accept this premise?) so this represents a net decrease of energy in the system (the reservoir). And recall that we haven't actually returned the system to its starting state, which would involve moving the buoyant object back to the main surface of the reservoir, which would take more energy to accomplish.
Repeatedly changing the phase of the buoyant material will also cost energy from the system. The difference in the energy of the buoyant material as it transitions from its solid to liquid states is the same as the difference as it transitions from liquid to solid. But again, there is no perpetual motion. Regardless of how the phase change happens, this costs energy from the system.
Even if the work done by the machine were sufficient to pay for the phase change, the system is still losing energy as the machine runs.
Tsehakla said:It doesn't really matter if the connection between the proposed mechanical and chemical parts of the system are direct/"causal" or indirect, because unless it is a closed system you don't have perpetual motion (as entropymancer pointed out).
Now, if you were to back away from the perpetual motion claim and try to use the ocean (or atmosphere) as an infinite capacity heat sink you would be in much the same game as the wave->energy and wind->energy people... and the question becomes, `can it be done more efficiently?'
Exactly.
Entropymancer said:I'm not sure that you are understanding... no matter how small the energetic cost to assemble the object, you're not going to have perpetual motion as long as the system is closed. You're losing energy in two places: doing work with the machine takes energy from the system, and assembling the object takes energy. No matter how small the energy to assemble the object is, you're never going to be able to use the work produced by the machine to replace the energy lost operating it if the system is closed.
You can only produce perpetual motion by opening the system to the environment so the lost energy can be compensated (in any of a variety of ways). And while this produces perpetual motion, it's not a perpetual motion machine. Perpetual motion is easy; I've got a solar powered flower gadget that perpetually bobs back and forth... but it's not a perpetual motion machine. It just gets the energy from an external source (the sun).
This is where you start relying on "magic"... if the object spontaneously disassembles it will not spontaneously reassemble, you will be left with its components dispersed throughout the medium--and it will be necessary to apply a force to do the work needed to "put 'em together right."SWIMfriend said:Tsehakla said:However, we can assume that the work required to transport the formerly buoyant object back down to the bottom, regardless of its form, will at least be equal to the work it took to get it to the surface because the same amount of mass needs to be moved the same distance.
No, I disagree there (and of course, if you're correct, the entire idea COMPLETELY fails). If the buoyant object is buoyant because of its FORM, and the form dissolves--you can then claim it can diffuse evenly throughout the water. Styrofoam (polystyrene) is just C and H--which can surely disperse and diffuse throughout any body of water; but put 'em together right, and you have something that's very buoyant, i.e., far less dense than water (I know I'm not strictly talking about "dissolving" in this case--but the logical principle is the same).
Logic is an abstract thing and doesn't apply any usable force; if it is sound it will lead you from truth to truth though. Keep in mind that thermodynamics is already discussed/expressed logically, using the language of mathematics (which is a sound logical system), so if it it wrong in some way you will be able to prove it using mathematics... that will most likely be easier and less error-prone than fiddling with mechanical and/or chemical systems.The main idea I'm trying to investigate is changing the LOGIC of the operation of a PM machine (or an apparatus that can produce work) such that you can circumvent the "work in = work out--at OPTIMUM" ultimate thermodynamic brick wall.
I suspect that "all" is too strong, but it really depends on how you define "traditional PM attempts." AFAICT, traditionally, all attempts at PM have failed.I'm not really trying to SELL this idea, so much as I am trying to remark that the scenario that I've outlined is QUALITATIVELY DIFFERENT from all other "traditional" PM attempts. I find the difference intriguing; that's all.
I'm fully granting that there's an energy cost to make the object disappear and reappear. I fully grant that it could be calculated exactly. And I fully grant (from my own experience) that in this case, it would no doubt require more energy than one can harvest just from the buoyant object going up the tube. What I'm saying is that it's only COINCIDENCE that things balance that way. It's only COINCIDENCE that more energy is required to MAKE things, than SOME of the contraptions those things could be a part of that produce energy.Tsehakla said:This is where you start relying on "magic"... if the object spontaneously disassembles it will not spontaneously reassemble, you will be left with its components dispersed throughout the medium--and it will be necessary to apply a force to do the work needed to "put 'em together right."
I think I expressed best how I see the problem in my last post. I'm not trying to say that thermodynamics is illogical. I guess what I'm saying is, that in such problems, one never includes calculations for the energy required to PRODUCE the elements used in the apparatus--when examining the thermodynamics of a process of the apparatus. In that way I mean that those elements of the apparatus exist almost AS abstractions--and the thermodynamic calculations don't end up addressing them.Tsehakla said:Logic is an abstract thing and doesn't apply any usable force; if it is sound it will lead you from truth to truth though. Keep in mind that thermodynamics is already discussed/expressed logically, using the language of mathematics (which is a sound logical system), so if it it wrong in some way you will be able to prove it using mathematics... that will most likely be easier and less error-prone than fiddling with mechanical and/or chemical systems.
hehe. I DO have an idea I want to investigate (when I get what I'm working on NOW off my table!). If it works, you will be among the FIRST to know, I promise. And if it FAILS, I will also describe it here and discuss where it fails, and what I didn't see. It's similar in that it depends on some aspects of change in the object, when subjected to static forces. In my mind it's very DIFFERENT from anything I've seen or heard approached or discussed; and the idea arose in the discussion of this business. But I'm not NEARLY in a position to understand how it would reflect on thermodynamics as it is now. Probably it's nothing. We'll see. I'll be happy to describe it as soon as I determine why it MUST fail. It doesn't involve anything as complex as producing objects--just "modifying them" during the process.Tsehakla said:If you do happen to rewrite the laws of thermodynamics, whether by mathematical proofs (i.e., logic) or by constructing a perpetual motion machine, make sure you put "swim" somewhere in the title so we know it was you.
SWIMfriend said:Entropymancer said:I'm not sure that you are understanding... no matter how small the energetic cost to assemble the object, you're not going to have perpetual motion as long as the system is closed. You're losing energy in two places: doing work with the machine takes energy from the system, and assembling the object takes energy. No matter how small the energy to assemble the object is, you're never going to be able to use the work produced by the machine to replace the energy lost operating it if the system is closed.
You can only produce perpetual motion by opening the system to the environment so the lost energy can be compensated (in any of a variety of ways). And while this produces perpetual motion, it's not a perpetual motion machine. Perpetual motion is easy; I've got a solar powered flower gadget that perpetually bobs back and forth... but it's not a perpetual motion machine. It just gets the energy from an external source (the sun).
I disagree. Ignoring the energetic cost of disassembling and reassembling the buoyant object, the rest of the apparatus supplies FREE ENERGY (ignoring friction, etc.). The cost of energy is pushing the buoyant object slightly under water, and the return is the full trip upward
Entropymancer said:I had thought you were just trying to violate the second law of thermodynamics... but from this statement it seems that you are trying to violate the first law as well!
Entropymancer said:Even with all of these idealized assumptions, we are still faced with the first law of thermodynamics... basically the law of conservation of energy. We still have ΔU = -W. That is, when we do some quantity of work, W, with the machine, the internal energy of the system (which in this case is the water reservoir and tube) decreases by that same amount of energy, W. The work isn't free, because we cannot spontaneously create energy out of thin air (recall that work is a form of energy). That energy has to come from somewhere, and in this case "somewhere" means the water reservoir/tube system.
SKA said:Hmm I've been thinking...
If you had such a setup as in the video, you could use a strong magnet connected to a buoyant airfilled balloon.
If the tube was square-shaped instead of cylindrical and attatched to the long side of a rectangulair water-reservoir,
then by letting the magnet-balloon float up in the square-shaped shaft, a metal object (attracted by the strong magnet) could be lifted along the
outside of the square shaft, untill it could be dropped from significant hight to yield energy.
The balloon could be deflated to sink the magnet and restart the cycle.
You'd need a proper magnet though. Perhaps one of those found in busted soundsystems are powerfull enough.
Then I'd need to figure out how to release the metal object from the magnet and inflating/deflating the balloon,
without using more energy than the falling metal objects can yield.
If that would work than it would pretty much be a perpetual motion device giving energy output in the form of electricity.
I should get to my drawing book. =)
Depending on how that statement is meant to be interpreted, it's either completely false or completely pointless: If you consider an object dissolving to be a form of "disappearing", it's totally false. Thermodynamic formulas account for things such as dissolving materials and phase changes. If you mean literally disappearing, then it's completely pointless. The only way for matter to cease to exist is to turn into energy.SWIMfriend said:To refute that you can't retreat to "thermodynamic formulas." Those formulas don't RECKON with disappearing objects (just as they don't reckon with forces that can be turned on and off at no cost).
SWIMfriend said:How about answering this: Do you agree with me that, if one could turn the magnetic force on and off at no cost, that it would be child's play to develop a PM machine--or a machine that would supply infinite free energy? The machine could simply be a suspended magnet over a metal object. When the magnet turns on the object is lifted in a gravitational field, and when turned off it falls in a gravitational field. Force over a distance is work. One could harvest an infinite amount of work/energy from such an apparatus.
That's because forces that can turn on an off for free must necessarily be incapable of applying any force. Objects that can disappear and reappear at different places (without applying the appropriate compensating energy) must necessarily be objects which are incapable of having any potential energy (which is to say, they must have no mass).So, the relevant "laws" don't take into account forces that can be turned on and off for free, or (as in the example under discussion) objects that can disappear and reappear at different places within a system of static forces (i.e., varying potential energies).
No. The equation states that the work produced is equal to the difference between the total internal energy of the object, reservoir, and tube combined, before and after the buoyant object rises. It seems that you're still missing that point: The work energy is not extracted from the buoyant object only, but from the water reservoir as well. And in a closed system, dissolving the buoyant object restores none of the internal energy of the system that has been lost to work.SWIMfriend said:...it's true, the potential energy of the buoyant object at the bottom of the tube is EQUIVALENT to the work produced as it rises up the tube (that's what your equation states).