- Merits
- 42
Sometimes access to solvents may vary for a plethora of reasons , so people might have to do with sub-optimal solvents. If you ask me, i would rather have the best purity solvents accompanied with a full analysis everytime, but sometimes that is just a dream.
Given the above, a company supplied the MSDS of solvents it sold. Lets say that distillation is not a possible route.
Solvent A contains : Xylene (mixed isomers) 75-80%, Ethylbenzene 10-30%
Solvent B contains : Toluol
% , Methanol >3%, Methylene Chloride stabilisers 85-90%
Solvent C contains : Xylene (its CAS is O-Xylene) 80%, n-butanol 20%
Some Questions on them:
1) If one wanted to extract using an aromatic solvent would Solvent A be suitable? I hear ethylbenzene commonly exists in xylene formulations, its aromatic ok, but i do not know much about its properties.
2) Could Solvents B and C be seperated without distilation?
(Clarification: Solvent B mentions "methylene Chloride stabilisers", it gives the CAS of methylene chloride so i assume its methylene chloride and stabilisers, i dont know how often CH2Cl2 has stabilisers in ,but i assume it may form dangerous brakedown products)
Bear with me but my chemistry knowledge is not my strong point but:
2a) If Solvent C is extracted with WATER, would the more polar n-butanol migrate to the water layer ,efficiently leaving xylene on the upper layer?
2b) If Solvent B is extracted with WATER , would toluol and methanol be seperated from it, toluol forming an upper layer and methanol going in the aqueous phase and methylene chloride forming a bottom layer?
I am not that sure the above could work, propably i need lots of studying in solvent systems. They seem unlikely to be so easily seperated,after all why would one employ distilation if it was so easy, but i thought i should ask for the input of someone more knowledgable.
Given the above, a company supplied the MSDS of solvents it sold. Lets say that distillation is not a possible route.
Solvent A contains : Xylene (mixed isomers) 75-80%, Ethylbenzene 10-30%
Solvent B contains : Toluol
Solvent C contains : Xylene (its CAS is O-Xylene) 80%, n-butanol 20%
Some Questions on them:
1) If one wanted to extract using an aromatic solvent would Solvent A be suitable? I hear ethylbenzene commonly exists in xylene formulations, its aromatic ok, but i do not know much about its properties.
2) Could Solvents B and C be seperated without distilation?
(Clarification: Solvent B mentions "methylene Chloride stabilisers", it gives the CAS of methylene chloride so i assume its methylene chloride and stabilisers, i dont know how often CH2Cl2 has stabilisers in ,but i assume it may form dangerous brakedown products)
Bear with me but my chemistry knowledge is not my strong point but:
2a) If Solvent C is extracted with WATER, would the more polar n-butanol migrate to the water layer ,efficiently leaving xylene on the upper layer?
2b) If Solvent B is extracted with WATER , would toluol and methanol be seperated from it, toluol forming an upper layer and methanol going in the aqueous phase and methylene chloride forming a bottom layer?
I am not that sure the above could work, propably i need lots of studying in solvent systems. They seem unlikely to be so easily seperated,after all why would one employ distilation if it was so easy, but i thought i should ask for the input of someone more knowledgable.