Dear Nexus
Dear downwardsfromzero
I have tried to take a closer look at the chemistry of salting out in Syrian rue extraction and have used Claude (AI) to write out chemical formulas and equations and help better my understanding.
I now want to present what I have learned and visualized. This might help other novices and from experts I kindly ask to be corrected for errors in my understanding.
For convenience I will only consider harmine and not harmaline.
After adding 10% table salt to a solution of harmine in vinegar we expect the following ions to be present:
Acetic acid anion: Ac-
Chloride anion: Cl-
Sodium cation: Na+
Harmine protonated: HH+
protons: H+
Provided that these ions can form precipitates with each other one can write out so-called solubility products and equilibrium constants for them. We use solubility products when dealing with precipitate-solute equilibria and we use equilibrium constants for solute-solute equilibria. Solubility products are just equilibrium constants with the conc. of the solid phase in equilibrium integrated directly into the constant:
For instance the solubility product for table salt:
View attachment 102212
The equilibrium constant (aka acid dissociation constant) of aq. vinegar and its aq. conjugate base (acetic acid anion):
View attachment 102213
The equilibrium constant of harmine and protonated harmine:
View attachment 102214
The solubility product of protonated harmine and Cl-..
View attachment 102215
..which is in equilibrium with the precipitate of protonated harmine and Cl-:
View attachment 102216
The solubility product and equilibrium constant should always remain the same at constant temperature, pressure and assuming we have a dilute solution (is manske solution considered dilute?).
Looking at the solubility product of protonated harmine and Cl-, raising Cl- (by adding table salt), if Ksp of protonated harmine Cl- is low and is to remain the same, aq harmine H+ needs to fall out of solution to rebalance the Ksp.
When we salt out we raise the solution temperature, raising the Ksp and allowing for the 10% NaCl solution to dissolve alongside everything else. Once the temperature drops of, the Ksp lowers as well and only now does harmine H+ need to fall out to account for the increase in Cl-.
Some further questions I now have:
1. Does this explain salting out in its entirety or do I need to consider additional stuff, like ionic strengths?
2. What form does harmine mainly take when dissolved in vinegar?
Will it be this:
View attachment 102217
3. Or could we also encounter a version with a further proton attached to the indole ring?
Like so:
View attachment 102218
4. If I dissolve Harmine in aq. HCL and add everclear to crash it out, would this produce the same precipitate we are talking about here?
Im assuming that adding alcohol would once again decrease the Ksp and therefore force protonated Harmine Cl- to crash out.
Lastly I want to mention that I plan to experiment on harmala tinctures and share the results. I still cannot make harmala soluble at concentrations high enough for convenience (say 20mg per ml). Does everyone here just work with the powder?
Kind regards
BUJU