thecosmicjoke
Esteemed member
Hello,
Over the coming months I plan to do a research paper on optimizing percent yield over an A/B and STB extraction of mimosa hostilis root bark. This is going to be an admittedly amateur paper as my knowledge and equipment are both relatively entry level. However, I find great satisfaction in no longer simply following procedures, but having enough chemistry knowledge to make my own decisions. That being said, it seems that the recommended amount of NaOH to be used for most procedures is just insanely off the mark. A pH of 14 can be attained with 30 grams of NaOH and 750mL distilled water. I have seen recommendations go all the way up to 100 grams, which is expensive, dangerous, and completely unnecessary.
I'm also not even entirely sure how necessary a pH of 14 (often recommended) even is for any STB or A/B extraction. I have heard (and would love if somebody can expand on this) that the amount of freebase to salt ratio of DMT at a pH of 8.68 is 50%. At pH 10.68%, 99% is freebase, which is important of course to be soluble in non-polar solutions. So if this is true, there is not really much benefit to achieving a pH higher than 11-12.
I'm curious if anybody has any insight onto why such a high pH is recommended for STB extracts. It's possible that the root bark is acidic and affects the alkalinity, but surely it is not that much. I only have pH papers so testing this isn't possible due to the color of the solution after the bark is added. The really funny thing is that if a pH of 12 is sufficient, this can be achieved with 0.3 grams of NaOH (for 750mL water).
I'd also appreciate any misunderstandings I have. My math is (0.3g NaOH) x (1mol/40gNaOH) = (0.0075mol NaOH) / (0.750L Solute) = 0.01M, -log(0.01)=2pOH, therefore pH=12.
I did the same for a modified A/B extraction I am running where I first soaked the bark in 750mL of a 0.83M Acetic Acid solution (5% distilled white vinegar). With this I am given DMT-Acetate which is water-soluble, so to the acidic solution I add enough NaOH to not only neutralize but to bring the pH up to 12 again (IF 12 is even sufficient, would love if somebody could comment on that). This should require 25.22g NaOH (1:1 mol ratio for neutralization, 750mL of 0.83M AA is 0.623 mole's Acetic Acid, therefore 0.623 moles of NaOH + 0.3 grams of NaOH (from earlier) is 25.22 grams NaOH).
One last thing, I found a research paper on different organic solvents for DMT extraction, with n-hexane actually found to be the worst performing (Internet method for the extraction of N,N-dimethyltryptamine from Mimosa hostilis roots: Does it really extract dimethyltryptamine?). Would love if somebody also had insight on this. For the longest time I would do simple Naptha pulls until I realized (after far longer than I should have) that my final product was certainly impure and contaminated with plant fats and alkaloids, and quite likely hydrocarbons and alkenes in the Naptha. This prompted me to order n-heptane to do re-x's which generally lead to roughly a 10% "decrease" in product. It's huge to be clearing out 10% of a product to impurities that I have been consistently consuming. Makes me concerned.
Anyways, this was possibly a rant. Would really enjoy some discussion and insights on what I have mentioned, mainly the pH concerns.
Thank you.
Over the coming months I plan to do a research paper on optimizing percent yield over an A/B and STB extraction of mimosa hostilis root bark. This is going to be an admittedly amateur paper as my knowledge and equipment are both relatively entry level. However, I find great satisfaction in no longer simply following procedures, but having enough chemistry knowledge to make my own decisions. That being said, it seems that the recommended amount of NaOH to be used for most procedures is just insanely off the mark. A pH of 14 can be attained with 30 grams of NaOH and 750mL distilled water. I have seen recommendations go all the way up to 100 grams, which is expensive, dangerous, and completely unnecessary.
I'm also not even entirely sure how necessary a pH of 14 (often recommended) even is for any STB or A/B extraction. I have heard (and would love if somebody can expand on this) that the amount of freebase to salt ratio of DMT at a pH of 8.68 is 50%. At pH 10.68%, 99% is freebase, which is important of course to be soluble in non-polar solutions. So if this is true, there is not really much benefit to achieving a pH higher than 11-12.
I'm curious if anybody has any insight onto why such a high pH is recommended for STB extracts. It's possible that the root bark is acidic and affects the alkalinity, but surely it is not that much. I only have pH papers so testing this isn't possible due to the color of the solution after the bark is added. The really funny thing is that if a pH of 12 is sufficient, this can be achieved with 0.3 grams of NaOH (for 750mL water).
I'd also appreciate any misunderstandings I have. My math is (0.3g NaOH) x (1mol/40gNaOH) = (0.0075mol NaOH) / (0.750L Solute) = 0.01M, -log(0.01)=2pOH, therefore pH=12.
I did the same for a modified A/B extraction I am running where I first soaked the bark in 750mL of a 0.83M Acetic Acid solution (5% distilled white vinegar). With this I am given DMT-Acetate which is water-soluble, so to the acidic solution I add enough NaOH to not only neutralize but to bring the pH up to 12 again (IF 12 is even sufficient, would love if somebody could comment on that). This should require 25.22g NaOH (1:1 mol ratio for neutralization, 750mL of 0.83M AA is 0.623 mole's Acetic Acid, therefore 0.623 moles of NaOH + 0.3 grams of NaOH (from earlier) is 25.22 grams NaOH).
One last thing, I found a research paper on different organic solvents for DMT extraction, with n-hexane actually found to be the worst performing (Internet method for the extraction of N,N-dimethyltryptamine from Mimosa hostilis roots: Does it really extract dimethyltryptamine?). Would love if somebody also had insight on this. For the longest time I would do simple Naptha pulls until I realized (after far longer than I should have) that my final product was certainly impure and contaminated with plant fats and alkaloids, and quite likely hydrocarbons and alkenes in the Naptha. This prompted me to order n-heptane to do re-x's which generally lead to roughly a 10% "decrease" in product. It's huge to be clearing out 10% of a product to impurities that I have been consistently consuming. Makes me concerned.
Anyways, this was possibly a rant. Would really enjoy some discussion and insights on what I have mentioned, mainly the pH concerns.
Thank you.
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