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emulsion questions - please enlighten me!

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xudface

Rising Star
hi guys!

recently someone was doing a pretty standard extraction from MHRB using HCL, NaOH and naphtha. after shaking a bit too much an emulsion layer was built up with the naphtha and the basic solution. to remedy the situation this person separated off the emulsified layer and put it on the windowsill in the hope that the solvent would evaporate and leave behind crystals which would be insoluble in the remaining solution.

much to the delight of the experimenter this is exactly what happened. there were some nice crystals floating on the red solution, and also some that had sunk to the bottom. to obtain the crystals more naphtha was added in the hope that they would dissolve in the naphtha which could then be easily separated. what actually happened though was that the crystals were NOT soluble in either the naphtha OR the aqueous solution. Also still some of the crystals floated between the two solutions, where as some sank right to the bottom. could somebody here please explain these findings for me as i don't understand what is happening here.

this was actually very beneficial because it allowed for the crystals to be obtained by simply draining off all the liquids. this even gave them a convenient little wash at the end! the crystals were sampled and found to be of a very high quality!
 
hi there mate
if im not mistaken the spice is only soluble in an aqueous solution if the solution
is acid , so if you have a basified solution , try to bring the ph down until da spice
melts in solution , for the emulsion problem , raising the ph innit will separate emulsions quickly, so add a bit more of naoh depending on your tek ,calculate or measure with a ph pen/paper 11.5(el ka bong) 13.(noman) take your pick
hope it helps
 
the freebase dissolves in naphtha. why didn't it dissolve back in the naphtha when i added more? i mean it's not a huge deal, but i just don't see why it wouldn't.
 
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