dumbstruck
Rising Star
I hate to ask for these fairly simple little questions that I ought to be able to figure out, but alas, I am stuck with a wide potential range of values.
I have 2400 ml of dried Xylene -- a total of four pulls done on 250 grams of strong San Pedro powder. I plan to add about 150 ml of dried, HCL saturated acetone to the lot of it to crash out Mesc HCl; how much 33% HCL acid solution should I use? The best number I came up with was 8.33 ml of 33% muriatic acid to be sufficient, but this seems like way way way too much. I unfortunately have no pH papers presently. Can anyone help clear this up for me?
edit: Further number crunching has me thinking the other end of my wide range of values is correct. I am going to use 1 ml of 33% muriatic acid hopefully in total. I will prepare 300 ml of acetone with 2 ml of 33% HCL, dry it, and plan to only use 150 ml. I'll separate the solvent from the crystals and add some more HCL laden acetone to see if anything else precipitates. If anyone knows more clearly how much I should use I would still like your input.
I have 2400 ml of dried Xylene -- a total of four pulls done on 250 grams of strong San Pedro powder. I plan to add about 150 ml of dried, HCL saturated acetone to the lot of it to crash out Mesc HCl; how much 33% HCL acid solution should I use? The best number I came up with was 8.33 ml of 33% muriatic acid to be sufficient, but this seems like way way way too much. I unfortunately have no pH papers presently. Can anyone help clear this up for me?
edit: Further number crunching has me thinking the other end of my wide range of values is correct. I am going to use 1 ml of 33% muriatic acid hopefully in total. I will prepare 300 ml of acetone with 2 ml of 33% HCL, dry it, and plan to only use 150 ml. I'll separate the solvent from the crystals and add some more HCL laden acetone to see if anything else precipitates. If anyone knows more clearly how much I should use I would still like your input.