shroombee, feel free to summarize and update any concepts that are not documented well. The nexus is what we make of it. The mescaline Teks are a little dated and maybe a fresh update would be good.
Anything that is soluble in both phases will be in both. However, there will be a concentration ratio (partition) driven by the chemical potential (which you can read about). I think some people jump to the erroneous conclusion that because salt is not soluble in solvent, then conversely, the FB is not soluble in water. If I recall, ron69 was washing his limo with basic water until he figured out he was pulling FB mescaline into the water and losing product. When people do wash with the solvent with water they typically use brine to saturate the water with ions and make it less likely for FB to go in it (minimize losses). I believe we have a DMT Tek in the Wiki (Noman's?) that uses carbonate water washes, it doesn't yield as well as other Teks but it is designed for purity I believe.
Intuitively, the molecules diffuse to occupy the entire volume if they can. Kind of like a a gas diffusing between two rooms.
When you do multiple pulls, the situation is equivalent to a bouncy ball that looses a fraction of it's energy after each bounce (perhaps this is more intuitive?). How many pulls you need to remove product ammount X is equivalent to how many bounces you need to remove energy (or bounce height) X.
For example, imagine a ball that looses 40% of it's energy with each bounce (that is, each bounce is 60% as tall as the previous height). Starting with from a height of 100 inches,
-After one bounce, the ball reaches 60 inches (40 inches lost = 40% yield after one pull)
-After the second bounce, the ball will reach 36 inches (24 lost in this bounce + 40 from before is 64 inches total lost = 64% yield after second pull).
Note: After or two bounces we can tell how big the initial height is, even if we never saw the initial position of the ball. In other words, we can estimate the total amount of product by measuring the first two pulls: 40 in the first pull (M1) and 24 in the second pull (M2) can estimate the total amount of product (MT) with the simple formula MT = M1^2/(M1-M2) = 40^2/(40-24) = 1600/16 = 100. I think this is kind of cool.
- After three bounces, ball will bounce 21.6 inches (14.4 lost on this point). The height (energy) removed is now 40 + 24 + 14.4 = 78.4.
- What happens after the 4th bounce is left to the reader. Finally after 5 bounces, the height (energy) removed is 92.224, equivalent to 5 pulls yielding 92.224%.
It's fun that the bouncing ball is mathematically equivalent to pulling drugs. It gives a new meaning to "I'm as high as balls"
